Function 1:
For the given table
[tex]\begin{array}{cc}x&f(x)\\-2&-2\\-1&1\\0&4\\1&7\end{array}[/tex]
you can plot the graph of the function (see first attached diagram). This function is linear and has equation f(x)=3x+4.
Function 2:
For the given function f(x)=-2x+3 you can create a table
[tex]\begin{array}{cc}x&f(x)\\-2&7\\-1&5\\0&3\\1&1\end{array}[/tex]
and plot the graph (see second attached diagram).
Function 3:
For the given graph of the function, you can find the function:
[tex]\dfrac{x-0}{6-0}=\dfrac{y-(-3)}{0-(-3)},\\ \\\dfrac{x}{6}=\dfrac{y+3}{3},\\ \\2(y+3)=x,\\ \\y=\dfrac{1}{2}x-3.[/tex]
Thus, the equation of the function 3 is [tex]f(x)=\dfrac{1}{2}x-3.[/tex]
The table will take a look
[tex]\begin{array}{cc}x&f(x)\\-2&-4\\-1&-3.5\\0&-3\\1&-2.5\end{array}[/tex]