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What is the equation in point-slope form of a line that passes through the points (7, −8) and (−4, 6) ?

y−6=−14/11(x+4)

y+6=−2/3(x−4)

y−6=−2/3(x+4)

y+6=−14/11(x−4)

Respuesta :

gmany

The slope-point form:

[tex]y-y_1=m(x-x_1)[/tex]

The formula of a slope:

[tex]m=\dfrac{y_2-y_1}{x_2-x_1}[/tex]

We have the points (7, -8) and (-4, 6). Substitute:

[tex]m=\dfrac{6-(-8)}{-4-7}=\dfrac{14}{-11}=-\dfrac{14}{11}\\\\y-6=-\dfrac{14}{11}(x-(-4))\\\\\boxed{y-6=-\dfrac{14}{11}(x+4)}[/tex]

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