Mei has 8 jars and each is 300ml
so she will need to times 8 by 300ml = 2400ml.
She needs a pot that holds 2400ml at least
(Actually, she needs a bigger pot because it needs to hold 2400ml so if the pot is that size the liquid will spill)
Answer:
the smallest container which can contain soup of 8 jar will be of size 2400 milliliters
Step-by-step explanation:
Mei has soup = 8 jars
Jar contains soup = 300 milliliters
to calculate the smallest post needed to heat all the soup together.
The container should be able to incorporate the 8 jars hence the smallest size of container will be
= number of jar × soup quantity
= 8 × 300
= 2400 milliliters
hence, the smallest container which can contain a soup of 8 jars will be of size 2400 milliliters.
