Respuesta :

[tex]\bf (\stackrel{x_1}{-2}~,~\stackrel{y_1}{2})\qquad (\stackrel{x_2}{-2}~,~\stackrel{y_2}{-3}) \\\\\\ slope = m\implies \cfrac{\stackrel{rise}{ y_2- y_1}}{\stackrel{run}{ x_2- x_1}}\implies \cfrac{-3-2}{-2-(-2)}\implies \cfrac{-3-2}{-2+2}\implies \stackrel{und efined}{\cfrac{-5}{0}}[/tex]


so our slope is undefined, that means a vertical line, check the picture below

Ver imagen jdoe0001
abidemiokin

The equation of the line shown in this graph passing through the points (-2, 2) and (-2, -3) is x = -2

The standard equation of a line graph is expressed as y = mx + b

m is the slope of the line

b is the y-intercept

Given the coordinate points  (-2, 2) and (-2, -3)

Slope  = -3-2/-2+2

Slope = -5/0

Slope  = [tex]\infty[/tex]

Since the slope of infinity, this shows that the line is a vertical line. The standard equation of a vertical line is x = a

Since the x-coordinates are similar, hence a = -2

The equation of the line shown in this graph passing through the points (-2, 2) and (-2, -3) is x = -2

Learn more here: https://brainly.com/question/24642959