Respuesta :

trevordoyleione

a) area of a triangle = (base X height) / 2 = 16X9/2 = 72cm squared

b) area of a parallelogram = (base X height) = 26 X 14 = 364 in squared

c) area of  a square =  (base X width) = 11 X 11 - 121 yds sqaured

d) are of a trapezoid (the hardest) =

(top bases + bottom base) /2 all times height

(6   +   21) /2  times 8

126/2 times 8

63 times 8 = 504 ' squared

david111602

Answer:

A = 72 cm^2

B = 364 in^2

C = 121 yd^2

D = 504'^2

explanation step by step

a) area of a triangle = (b x h) / 2 = 16 X 9 /2 = 72 cm^2

A = 72 cm^2

b) area of a parallelogram = (b x h) = 26 X 14 = 364 in^2

B = 364 in^2

c) area of  a square =  (b x h) = 11 X 11 = 121 yd^2

C = 121 yd^2

d) are of a trapezoid  = (b1 + b2 /2 all times height

(6 + 21) / 2 x 8

126 / 2 x 8

63 x 8 = 504'^2

D = 504'^2

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