when a marble started from rest we can say that
initial velocity of the marble is
[tex]v_i = 0[/tex]
now it took t = 1.4 s to cover total distance of 54 cm by the marble.
so here we will have use kinematics equation in order to find the acceleration of the marble
so we can use
[tex]d = v_i* t + \frac{1}{2}at^2[/tex]
d = 54 cm = 0.54 m
we will plug in all data
[tex]0.54 = 0 * 1.4 + \frac{1}{2}*a * 1.4^2[/tex]
[tex]0.54 = 0 + 0.98*a[/tex]
[tex]a = \frac{0.54}{0.98}[/tex]
[tex]a = 0.55 m/s^2[/tex]
so the acceleration of the marble will be 0.55 m/s^2 on the given ramp
