Respuesta :
(5) use the points (20,10) and (70,110)
slope = [tex]\frac{y_2-y_1}{x_2-x_1}[/tex]
(20,10) is (x1,y1) and (70,110) is (x2,y2)
slope = [tex]\frac{110-10}{70-20}=2[/tex]
so slope = 2
the point-slope equation of the trend line is
[tex]y - y_1 = m(x - x_1)[/tex]
m is the slope. m=2, x1= 20 and y1= 10
[tex]y - 10 = 2(x - 20)[/tex]
The point slope equation is y - 10 = 2(x - 20)
(6) rewrite the equation you found in question 5 in slope-intercept and standard form
y - 10 = 2(x - 20)
To find slope intercept form we need to get y alone,
distribute 2 inside the parenthesis
y - 10 = 2x - 40
Add 10 on both sides
Slope intercept form is y = 2 x - 30
Standard form is Ax + By = C
y = 2x - 30
Subtract 2x from both sides
-2 x + y = -30
