Determine the vertical change of a line with an x-intercept at (-4, 0) and a y-intercept at (0, 5). Type a numerical answer in the space provided. If necessary, use the / key as a fraction bar. Do not type spaces in your answer. a0.

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Gyzmo

y=ax+b

Slope=5/4

y=5/4x+b

y-intercept=5

y=5/4x+5

Step-by-step explanation:

Consider the provided information.

It is given that the x-intercept at (-4, 0) and a y-intercept at (0, 5).

The slope of a line is m =[tex]\frac{Rise}{Run}[/tex]

Where Rise represents the vertical change and Run represents the horizontal change.

Or we can say the slope of a line is vertical change divided by the horizontal change.

For the coordinate [tex](x_1, y_1)\ \text{and} \ (x_2, y_2)[/tex] the slope is:

[tex]m=\frac{y_2-y_1}{x_2-x_1}[/tex]

Now substitute [tex](x_1, y_1)=(-4,0)\ \text{and} \ (x_2, y_2)=(0,5)[/tex] in above formula.

[tex]m=\frac{5-0}{0-(-4)}[/tex]

[tex]m=\frac{5}{4}[/tex]

Thus, the slope of the line is 5/4.

The equation of line is y=5/4x+5, where 5 is the y intercept.

The vertical change of the line is 5 unit and horizontal change is 4 unit.