Pam's eye–level height is 256 feet above sea level and Adam's eye–level height is 400 feet above sea level. What expression shows how much farther Adam can see to the horizon?

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Answer:

To solve this problem, we need to use the following formula

[tex]d=\sqrt{\frac{3h}{2} }[/tex]

Where [tex]h[/tex] is the eye-level height and [tex]d[/tex] is the horizontal distance to the horizon.

For Pam, we know that [tex]h=256ft[/tex],

[tex]d=\sqrt{\frac{3(256)}{2} }=\sqrt{384} \approx 19.6[/tex]

She can see around 19.6 feet to the horizon.

For Adam, we know that [tex]h=400 ft[/tex]

[tex]d=\sqrt{\frac{3(400)}{2} }=\sqrt{600} \approx 24.5[/tex]

He cansee around 24.5 feet to the horizon.

Now, the difference is

[tex]\Delta d= d_{Adam} -d_{Pam} \\\Delta d= 24.5 - 19.6 = 4.9[/tex]

Therefore, Adam can see 4.9 feet much farther than Pam.

Additionally, the expression that models this situation is [tex]\Delta d= d_{Adam} -d_{Pam}[/tex]

The distance between two points, is the number of units between them.

The expressions are: [tex]\mathbf{d = |400 - 256|}[/tex] and [tex]\mathbf{d = |256 - 400 |}[/tex]

The given parameters are:

[tex]\mathbf{Pam = 256ft}[/tex]

[tex]\mathbf{Adam = 400ft}[/tex]

The expression that shows the difference between their eye levels, is calculated using the following absolute equation.

[tex]\mathbf{d = |Adam-Pam|}[/tex] or [tex]\mathbf{d = |Pam -Adam|}[/tex]

So, we have:

[tex]\mathbf{d = |400 - 256|}[/tex] or [tex]\mathbf{d = |256 - 400 |}[/tex]

Hence, the expressions are: [tex]\mathbf{d = |400 - 256|}[/tex] and [tex]\mathbf{d = |256 - 400 |}[/tex]

Read more about absolute equations at:

https://brainly.com/question/2166748