Answer:
f(3) = 3^3 - 14*9 + 61*9 - 84 = 0 so 3 is one zero long division of the expression by (x - 3) gives the quadratic x^2 -11x + 28 which = (x - 7)(x-4) so the other zeros are 4 and 7, 3,4 and 7
Basically your answer is 7, 4, and 3
Step-by-step explanation:
5x^3-6x²-59x+12=5x^3-x²-5x²+x-60x+12 =x²(5x-1)-x(5x-1)-12(5x-1) =(5x-1)(x²-x-12) =(5x-1)(x²+3x-4x-12) =(5x-1)(x(x+3)-4(x+3)) =(5x-1)(x+3)(x-4) zeros are
And your answer for this is; 4, -3, 1/5
Hope this helped and good luck :)
(Brainliest is always appreciated)
