ASNSWER
[tex]Perimeter=\frac{5x-16}{2}[/tex]
EXPLANATION
Let [tex]w=x[/tex] represent the width of the rectangle.
One-fourth of the width will be,
[tex]\frac{1}{4}x[/tex]
Let [tex]l[/tex] represent the length of the rectangle.
Then, subtracting 4 units from one-fourth the width gives us the length
[tex]\Rightarrow l=\frac{1}{4}x-4[/tex]
Perimeter[tex]=2x+2l[/tex]
[tex]\Rightarrow Perimeter=2x+2(\frac{1}{4}x-4)[/tex]
We expand to obtain;
[tex]Perimeter=2x+\frac{x}{2}-8[/tex]
[tex]Perimeter=\frac{x+4x-16}{2}[/tex]
[tex]Perimeter=\frac{5x-16}{2}[/tex]