aoSrCl2 + a1 Li3PO4 → a2Sr3(PO4)2 + a3 LiCl
The coefficients that will balance the equation above are
ao= 3
a1=2
a2=1
a3=6
explanation
- The balanced equation is therefore as below
3SrCl2 +2Li3PO4→ Sr3(Po4)2 + 6 LiCl
- 3 moles of SrCL2 react with 2 moles of Li3PO4 to form 1 moles of Sr3(PO4)2 + 6 moles of LiCl
The balanced equation obey law of mass conversion of a chemical reaction since the mass of the product is equal to mass of reactant.
- for example in reactant side we have 3 Sr which is the same in product side.
