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The sum of two consecutive integers is –49. Write an equation that models this situation and find the values of the two integers.
n + n + 1 = –49; n = –25; n + 1 = –24
n + n + 1 = –49; n = –25; n + 1 = –26
n + 2n = –49; n = –17; 2n = –34
n + n + 1 = –49; n = –24; n + 1 = –23

Respuesta :

Answer:

The correct option is:  [tex]n + n + 1 = -49; n = -25; n + 1 = -24[/tex]

Step-by-step explanation:

Suppose, the first integer is  [tex]n[/tex]

As the two integers are consecutive, so the second integer will be:  [tex]n+1[/tex]

Given that, the sum of two integers is -49.

So, the equation will be.........

[tex]n+(n+1)= -49\\ \\\Rightarrow 2n+1=-49\\ \\ \Rightarrow 2n=-50\\ \\ \Rightarrow n=\frac{-50}{2}=-25[/tex]

Thus, the first integer is, [tex]n= -25[/tex] and the second integer is, [tex]n+1= -25+1= -24[/tex]

Answer:

The correct option n + n +1 = -49;n = -25; n + 1 = -24

Step-by-step explanation:

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