Help ASAP!!! Problem is on the picture provided.

QUESTION 1
The volume of a cone is given by;
[tex]V=\frac{\pi r^2h}{3}[/tex]
From the given information,
[tex]r=12,h=6[/tex]
[tex]V=\frac{12^2\times 6}{3}\pi[/tex]
[tex]V=\frac{144 \times 6}{3}\pi[/tex]
[tex]V=288\pi[/tex]
QUESTION 2
The volume of a sphere is given by
[tex]V=\frac{4\pi r^3}{3}[/tex]
From the given information.\
[tex]r=\frac{Diameter}{2}= \frac{12}{2}=6[/tex]
Therefore the volume of the sphere is
[tex]V=\frac{4\times6^3}{3} \pi[/tex]
[tex]V=\frac{4\times216}{3} \pi[/tex]
[tex]V=288\pi[/tex]
QUESTION 3
The volume of a sphere is given by
[tex]V=\frac{4\pi r^3}{3}[/tex]
From the given information.\
[tex]r=9[/tex]
Therefore the volume of the sphere is
[tex]V=\frac{4\times 9^3}{3} \pi[/tex]
[tex]V=\frac{4\times 729}{3} \pi[/tex]
[tex]V=972\pi[/tex]
QUESTION 4
The volume of a cylinder is given by
[tex]V=\pi r^2 h[/tex]
From the given information,
[tex]r=\frac{Diameter}{2}= \frac{12}{2}=6[/tex]
and
[tex]h=27[/tex]
Therefore volume of the cylinder
[tex]V=6^2 \times 27 \pi[/tex]
[tex]V=36 \times 27 \pi[/tex]
[tex]V=972\pi[/tex]
QUESTION 5
The volume of a cylinder is given by
[tex]V=\pi r^2 h[/tex]
From the given information,
[tex]r=\frac{Diameter}{2}= \frac{8}{2}=4[/tex]
and
[tex]h=18[/tex]
Therefore volume of the cylinder
[tex]V=4^2 \times 18 \pi[/tex]
[tex]V=16 \times 18 \pi[/tex]
[tex]V=288\pi[/tex]
QUESTION 6
The volume of a cone is given by;
[tex]V=\frac{\pi r^2h}{3}[/tex]
From the given information,
[tex]r=\frac{18}{2}=9,h=36[/tex]
[tex]V=\frac{9^2\times 36}{3}\pi[/tex]
[tex]V=\frac{81 \times 36}{3}\pi[/tex]
[tex]V=972\pi[/tex]
Volume of a cone = [tex]\pi r^2\frac{h}{3}[/tex]
Volume of a sphere = [tex]\frac{4}{3} \pi r^3[/tex]
Volume of a cylinder = [tex]\pi r^2h[/tex]
With the help of these formulas, we can calculate the volumes.
A cone with a radius of 12 units and a height of 6 units = [tex]\pi 12^2\frac{6}{3}[/tex] = 288[tex]\pi[/tex]
A sphere with a diameter of 12 units = [tex]\frac{4}{3} \pi 6^3[/tex] = 288[tex]\pi[/tex]
A sphere with a radius of 9 units = [tex]\frac{4}{3} \pi 9^3[/tex] = 972[tex]\pi[/tex]
A cylinder with a diameter of 12 units and a height of 27 units = [tex]\pi 6^227[/tex] = 972[tex]\pi[/tex]
A cylinder with a diameter of 8 units and a height of 18 units = [tex]\pi 4^218[/tex] = 288[tex]\pi[/tex]
A cone with a diameter of 18 units and a height of 36 units = [tex]\pi 9^2\frac{36}{3}[/tex] = 972[tex]\pi[/tex]