0.292 moles of S
The chemical formula (C₃H₅)₂S may be of di(prop-1-en-1-yl)sulfane or it may be of diallylsulfane. First let us find the number of moles of each elemnet present in one mole of (C₃H₅)₂S. i.e.
Element Moles
Carbon 6
Hydrogen 10
Sulfur 1
As one mole of (C₃H₅)₂S weights 114 g so we can calculate the number of moles of S in 33.3 g of (C₃H₅)₂S as,
114 g of (C₃H₅)₂S contains = 1 mole of S
Then,
33.3 g of (C₃H₅)₂S will contain = X moles of S
Solving for X,
X = (33.3 g × 1 mol) ÷ 114 g
X = 0.292 moles of S
