contestada

solve for x.
-15x+60<105 and 14x+11<-31
A). x<-3
B).x>-3
C).x=-3
D). there are no solutions
E). all caluse of x are dolutions

Respuesta :

wegnerkolmp2741o

-15x+60<105 and 14x+11<-31

-15x+60<105 subtract 60 from each side

-15x <45

divide by -15 (flips the inequality)

x>3


14x+11<-31

subtract 11 from each side

14x < -42

divide by 14

x<-3


Answer : there are no solutions since x>3 and x<-3 they are mutually exclusive (they both can't happen at the same time)

Answer:

c.=-3 is the correct answer I just did the test

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