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ANSWER

The point slope form is [tex]y-\frac{7}{5}=\frac{6}{19}(x+1)[/tex]


EXPLANATION


The point slope form of the equation of a straight line is given by the formula;

[tex]y-y_1=m(x-x_1)[/tex].


Where [tex]m[/tex] is the slope of the straight line and the point [tex](x_1,y_1)[/tex] lies on the line.


We were given the slope to be [tex]\frac{6}{19}[/tex]. This means that [tex]m=\frac{6}{19}[/tex].


We were also given that the point [tex](-1,\frac{7}{5})[/tex] lies on the line.


We substitute all these values in to the above equation to obtain,

[tex]y-\frac{7}{5}=\frac{6}{19}(x--1)[/tex]


This simplifies to


[tex]y-\frac{7}{5}=\frac{6}{9}(x+1)[/tex]


The correct answer is C

Answer:  Third option is correct.

Explanation:

Since we have given that

Slope of line is given by

[tex]\frac{6}{19}[/tex]

Passing through the point is given by

[tex](-1,\frac{7}{5})[/tex]

As we know the formula for "Point slope form" :

[tex](y-y_0)=m(x-x_0)[/tex]

So, we put the given value , such that

[tex](y-\frac{7}{5})=\frac{6}{19}(x+1)\\\\\frac{5y-7}{5}=\frac{6x}{19}+\frac{6}{19}\\\\19(5y-7)=5(6x+6)\\\\95y-133=30x+30\\\\95y-30x=30+133\\\\95y-30x=163[/tex]

Hence, Third option is correct.



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