what is the point slope form of the equation for the line with a slope of -8 that passes through the point (5, -3) ?

We know that the form of line passing through point (x₀ , y₀) and having slope m is :
[tex]\clubsuit[/tex] y - y₀ = m(x - x₀)
Here the line passes through the point (5 , -3)
⇒ x₀ = -2 and y₀ = -5
Given : Slope(m) = -8
Substituting all the values in the standard form, We get :
Equation of the line : y + 3 = -8(x - 5)
ANSWER
The point slope form is [tex]y+3=-8(x-5)[/tex]
EXPLANATION
The point slope form of the equation of a straight line is given by the formula;
[tex]y-y_1=m(x-x_1)[/tex].
Where [tex]m[/tex] is the slope of the straight line and the point [tex](x_1,y_1)[/tex] lies on the line.
We were given the slope to be [tex]-8[/tex]. This means that [tex]m=-8[/tex].
We were also given that the point [tex](5,-3)[/tex] lies on the line.
We substitute all these values in to the above equation to obtain,
[tex]y--3=-8(x-5)[/tex]
This simplifies to
[tex]y+3=-8(x-5)[/tex]
The correct answer is D