Respuesta :
Answer:
Usando movimiento vertical de los cuerpos, la altura de la torre es:
h = 28,224 m
Step-by-step explanation:
Si dejamos caer el objeto, su velocidad inicial es cero: Vo=0 m/s
Tiempo que tarda en llegar al suelo: t=2,4 s
Altura de la torre: h=?
La altura de la torre es la distancia que recorre el objeto desde que se deja caer hasta que llega al suelo, entonces podemos usar la formula de distancia:
h = d = Vo t +/- a t^2/2
La aceleracion del cuerpo es la que ejerce la gravedad porque es caida libre, y es positiva porque el cuerpo va en la misma direccion que la aceleracion de la gravedad (hacia abajo):
h = Vo t + g t^2/2
Tomando la aceleracion de la gravedad como:
g=9,8 m/s^2
Y reemplazando los valores conocidos en la formula:
h = (0 m/s) (2,4 s) + (9,8 m/s^2) (2,4 s)^2 / 2
h= 0 m + (9,8 m/s^2) (5,76 s^2) / 2
h = 56,448 m / 2
h= 28,224 m
La altura de la torre es 28,224 m
The height of the tower is [tex]\boxed{28.224{\text{ m}}}.[/tex]
Further explanation:
The second equation of the motion can be expressed as follows,
[tex]\boxed{H = ut + \frac{1}{2}g{t^2}}[/tex]
Here, [tex]u[/tex] represents the initial velocity, [tex]t[/tex] represents the time, [tex]H[/tex] represents the vertical distance and [tex]g[/tex] represents the acceleration due to gravity.
Given:
The time taken by the object to reach the ground is [tex]2.4{\text{ seconds}}.[/tex]
Explanation:
The object is dropped from the tower. Therefore, initial velocity is zero.
[tex]u = 0{\text{ m/s}}[/tex]
The value of acceleration due to gravity is [tex]9.8{\text{ m/}}{{\text{s}}^2}.[/tex]
The time taken by the object to reach the ground is [tex]2.4{\text{ seconds}}.[/tex]
The vertical distance or height of the tower can be obtained as follows,
[tex]\begin{aligned}H&= ut+\frac{1}{2}g{t^2}\\&=0\times 2.4 + \frac{1}{2} \times 9.8 \times {2.4^2}\\&= 0 + 4.9 \times 5.76\\&= 28.224{\text{ m}}\\\end{aligned}[/tex]
The height of the tower is [tex]\boxed{28.224{\text{ m}}}.[/tex]
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Answer details:
Grade: High School
Subject: Mathematics
Chapter: Motion
Keywords: average rate of change, drop an object, tower, top of a tower, the time, reach the ground, height of tower, ground, time, 2.4 seconds.