Answer:
[tex](103-x) 10[/tex] ft
Step-by-step explanation:
A Cheetah can run at 103 ft/s.
A Zebra can run at x ft/s.
We have to use distributive property, in the distributive property we multiply a sum by multiplying each addend separately and then add the products.
[tex]a \times (b+c)= a \times b + a \times c[/tex]
In ten seconds, Cheetah will cover,
[tex]10 \times 103 = 1030 ft[/tex]
In ten seconds, Zebra will cover,
[tex]x \times 10= 10 x ft[/tex]
So the distance by which Cheetah is farther than Zebra is,
[tex]1030 - 10x[/tex]
= [tex](103 -x) 10 ft[/tex] (Use of distributive property)
