Answer:
John has 16 quarters and 12 dimes
Step-by-step explanation:
Quarters are worth $0.25 each and Dimes are worth $0.10 each.
Let number of dimes John has be [tex]d[/tex] and number of quarters he has be [tex]q[/tex]
[tex]q-4=d[/tex]
This is Equation 1.
[tex]0.25q+0.1d=5.20[/tex]
This is Equation 2.
Now, substituting Equation 1 into Equation 2 and solving for q gives us:
[tex]0.25q+0.1(q-4)=5.20\\0.25q+0.1q-0.4=5.20\\0.35q=5.20+0.4\\0.35q=5.60\\q=16[/tex]
There are 16 quarters.
Now using this fact, we use this value in Equation 1 to get the number of dimes.
[tex]q-4=d\\16-4=d\\12=d[/tex]
There are 12 dimes.
Hence, John has 16 quarters and 12 dimes.
Answer:
16 quarters and 12 dimes
Step-by-step explanation:
Let 'q' be the number of quarter and 'd' be the number of dimes.
So he has,
[tex]0.25q+0.10d= 5.20[/tex] ......................... (i)
It is given that John has 4 more quarters than dimes, so we have,
[tex]q = d+4[/tex] ............................. (ii)
Putting the value of 'q' in equatioi (i), we get,
[tex]0.25(d+4)+0.10d=5.20[/tex]
[tex]0.25d+1+0.10d=5.20[/tex]
[tex]0.35d=5.20-1[/tex]
[tex]0.35d=4.20[/tex]
[tex]d=12[/tex]
Putting d = 12 in the equation (ii), we get,
[tex]q = 12+4 =16[/tex]
Therefore, John has 16 quarters and 12 dimes.
You can also verify the sum by multiplying 16 quarters with its value and adding the value of 12 dimes, you will get $5.20.
