If the gravitational force between the electron (9.11 ✕ 10-31 kg) and the proton (1.67 ✕ 10-27 kg) in a hydrogen atom is 1.26 ✕ 10-47 n, how far apart are the two particles?

Respuesta :

Gravitational force is given by the formula

[tex]F_g = \frac{Gm_1m_2}{r^2}[/tex]

here we know that

[tex]F_g = 1.26 \times 10^{-47}N[/tex]

[tex]m_1 = 9.11 \times 10^{-31} kg[/tex]

[tex]m_2 = 1.67 \times 10^{-27} kg[/tex]

now we will plug in all values in above equation

[tex]F_g = \frac{(6.67 \times 10^{-11})(9.11 \times 10^{-31})(1.67 \times 10^{-27})}{r^2}[/tex]

now solving for distance "r" between them

[tex]r = 8.97 \times 10^{-11} m[/tex]

so above is the distance between them

F = gravitational force between electron and proton = 1.26 x 10⁻⁴⁷ N

m = mass of proton = 1.67 x 10⁻²⁷ kg

M = mass of the electron = 9.11 x 10⁻³¹ kg

r = distance between electron and proton = ?

G = universal gravitational constant = 6.67 x 10⁻¹¹

gravitational force between electron and proton is given as

F = G M m/r²

inserting the values

(1.26 x 10⁻⁴⁷) = (6.67 x 10⁻¹¹) (1.67 x 10⁻²⁷) (9.11 x 10⁻³¹)/r²

r = 8.97 x 10⁻¹¹ m