Respuesta :
M = mass of the whale = 1000 kg
m = mass of the seal = 200 kg
V = initial velocity of whale before collision with the seal = 6.0 m/s
v = initial velocity of the seal before collision with the whale = 0 m/s
V' = final velocity of two sea creatures after collision = ?
Using conservation of momentum
M V + m v = (M + m) V'
inserting the above values in the equation
(1000 kg) (6.0 m/s) + (200 kg) (0 m/s ) = (1000 kg + 200 kg) V'
6000 kgm/s + 0 kgm/s = (1200 kg) V'
V' = (6000 kgm/s ) /(1200 kg)
V' = 5 m/s
Answer:
Pf = 6000 kg*m/s
Explanation:
Using the conservation of the linear momentum:
[tex]P_i = P_f[/tex]
Also:
[tex]P_i=M_bV_b[/tex]
[tex]P_f = (M_b+M_s)V_s[/tex]
Replacing:
[tex]M_bV_b = (M_b+M_s)V_s[/tex]
where [tex]M_b[/tex] is the mass of the whale, [tex]V_b[/tex] is the velocity of te whale, [tex]M_s[/tex] is the mass of the seal and [tex]V_s[/tex] is the velocity of both after the collition.
so:
[tex](1000 kg)(6 m/s) = (1000 kg+ 200kg)V_s[/tex]
Solving for [tex]V_s[/tex]:
[tex]V_s = 5 m/s[/tex]
Finally for find the momentum we will use the next equation:
[tex]P_f = (M_b+M_s)V_s[/tex]
Pf = (1000+200)(5 m/s)
Pf = 6000 kg*m/s
Alternative:
we know that the linear momentum is conserved so, we only have to know the initial momentum for have the answer:
[tex]P_i=M_bV_b[/tex]
Pi = (1000)(6 m/s)
Pi = 6000 Kg*m/s
