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Hi guys, can someone please help with this assignment :

For which value of p with the equation below have no real solution


px^2 + 4x + 6 = 0

I got so far, but stuck and not sure where to go further:


px^2 + 4x + 6 = 0 >> I divide then everything with p


x^2 + 4x/p + 6/p = 0


x= -4/2p +- √(-4/2p)^2 -6/p

x= -2/p +-√4/p -6/p


I'm not sure where to go from here. Can someone please help me.

Thanks in advanced for any help!

Respuesta :

If there is no real solution the Discriminant (b^2 - 4ac) will have a value less than zero.  The a, b and c refer to the coefficients in the equation

ax^2 + bx + c = 0.

So for this equation  to have no real solution 4^2 - 4*p * 6 < 0

-24p + 16 < 0

-24p < -16

p > 16/24

p > 2/3

So the value of p must be greater than 2/3 for no real solutions,  (answer).

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