What is the osmotic pressure of a 0.050 m solution of alcl3 in water that is at 0.00°c? consider alcl3 to be a strong electrolyte?

Respuesta :

Answer: Osmotic pressure of the given solution is 4.48 atm.

Explanation: Osmotic pressure is defined as the number of moles of solute which are present in a solution.

Mathematically,

[tex]\pi = icRT[/tex]     ....(1)

where i = Van't Hoff factor

c = concentration of the solution

R = Universal gas constant = [tex]0.0821\text{ atm L }mol^{-1}K^{-1}[/tex]

T = temperature of the solution

Value of 'i' is 1 for non-electrolytes. But, here [tex]AlCl_3[/tex] is an electrolyte, so the value of Van't Hoff factor will be the number of moles of particles of solute we get when 1 mole of solute is dissolved in a solution.

So, when 1 mole of [tex]AlCl_3[/tex] dissociates in aqueous state to produce 1 mole of [tex]Al^{3+}[/tex] ion and 3 moles of [tex]Cl^-[/tex] ion.

[tex]AlCl_3(aq.)\rightarrow Al^{3+}(aq.)+3Cl^-(aq.)[/tex]

For [tex]AlCl_3[/tex],

i = 4

c = 0.050 mol/L

T = (273 + 0)K = 273 K

Putting the values in equation 1, we get

[tex]\pi =4\times0.050mol/L\times0.0821\text{ atm L }mol^{-1}K^{-1}\times 273K[/tex]

[tex]\pi =4.48atm[/tex]