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Madi has $8.80 in pennies and nickels.
If there are twice as many nickels as pennies, how many pennies and nickels does Madi have?

0.01p + 0.05n = 8.80; n=???P

Respuesta :

Poz
Let p = number of pennies.
Let n = number of nickels.

We are given that n= 2p and the total value is $8.80.

We know that a penny = $0.01 and that a nickel = $0.05.

So $0.01p + $0.05n = $8.80.

Substitute 2p for n:
$0.01p + $0.05*2p = $8.80

$0.01p + $0.10p = $8.80

$0.11p = $8.80

p = 80
So n = 2p = 2*80 = 160

Thus there are 80 pennies ($0.8) and 160 nickels ($8.00). The value of all the coins is $8.80.

Madi has 80 pennies and 160 nickels.

Given that,

Madi has $8.80 in pennies and nickels.

If there are twice as many nickels as pennies.

We have to determine,

How many pennies and nickels does Madi have.

According to the question,

Equation; 0.01p + 0.05n = 8.80;

Let, p = number of pennies.

And, n = number of nickels.

If there are twice as many nickels as pennies n= 2p, and the total value is $8.80.

And pennies = $0.01 and that a nickel = $0.05.

Therefore,

$0.01p + $0.05n = $8.80.

Substitute the value of 2p = n in the given equation,

$0.01p + $0.05(2p) = $8.80

$0.01p + $0.10p = $8.80

$0.11p = $8.80

p = $8.80/$0.11

p = 80

And substitute the value of p=8 in the equation,

Then,

n = 2p = 2(80) = 160

Hence, There are p=80 pennies ($0.8) and n=160 nickels ($8.00). The value of all the coins is $8.80.

To know more about the System of equations click the link given below.

https://brainly.com/question/21145944

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