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a total of 937 people attended the play. admission was $2.00 for adults and $0.75 for students. the total ticket sale amounted to $1,109. how many students and adults attended the play?

Respuesta :

bunnymarshmarloykw47
To solve this question, we can set two equations:

Let x be number of adults and y be number of students.

As there are in total 937 people, the equation would be the sum of both adults and children:
x+y=937
x=937-y...(1)

As the total sale amount is $1109, the equation would be to add up the ticket fee:
2x+0.75y=1109...(2)

Put (1) into (2):

2(937-y)+0.75y = 1109
1874-2y+0.75y = 1109
-2y+0.75y = 1109-1874
-1.25y = -765
y = 763/1.25
y = 612

Put y into (1):
x = 973-612
x = 361

Therefore there are 612 adults abd 361 students.

Hope it helps!
deepakrai138

612 students and 325 adults attend the play.

Let the number of Adults attend the play be x and the number of students attend the play be y.

Given,

The total people attend the play is 937.

The admission fees for each adults was $2.

So the admission fees for x adults will be $2x.

The admission fees for each student was  $0.75.

So, the admission fees for y students will be $0.75y.

Now according to the question,

[tex]x+y=937......(1)[/tex]

[tex]2x+0.75y=1109.....(2)[/tex]

multiplying equation (1) by 2 we get,

[tex]2x+2y=1874[/tex]

Now subtracting equation (1) from the above equation we get,

[tex]1.25y=765[/tex]

[tex]y=\dfrac{765}{1.25}[/tex]

[tex]y=612[/tex]

Putting the value of y in equation (1) we get,

[tex]x+612=937[/tex]

[tex]x=325[/tex]

Hence the number of adults will be 325 and the number of students will be 612.

For more details on equation solving follow the link:

https://brainly.com/question/11897796

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