Respuesta :

The  number of grams  of  oxalic  acid  dihydrate  that are  needed  to react  with  20.00  ml  of 0.4500 M  NaOH is   0.567 grams


    calculation

 Step 1:   write the equation for reaction

H2C2 O4 . 2H2O + 2 NaOH →  Na2C2O4  + 4 H2O

Step 2:   calculate  the  moles of NaOH

 moles =  molarity  x  volume in liters

    volume in liters =  20.00/1000 =0.0200 L

   molarity  =0.4500 M =  0.4500  mol/l

moles = 0.4500 mol/l  x  0.0200 L  =0.0090  moles


Step  3: use the  mole ratio  to  calculate the  of oxalic acid  dihydrate

that is H2 C2O4: NaOH  is 1:2  therefore the moles  of H2C2O4.2H2O

   =0.0090 moles x 1/2 =0.0045   moles


Step  4:  calculate  the  mass  of  H2C2O4.2H2O

 mass= moles x  molar  mass

the  molar mass of H2C2O4.2H2O = (1x2)+ (12 x2) + (16 x4)  + 2(18)  =126 g/mol


mass  =0.0045  moles  x 126  g/mol =0.567 grams

0.567 grams of oxalic acid dihydrate, a diprotic acid are needed to react with 20.00 mL of 0.4500 M NaOH.

How we calculate mass of any substance from moles?

Mass of any substance will be calculated by using moles as:

n = W/M, where

W = required mass

M = molar mass

Given chemical reaction is :
H₂C₂O₄.2H₂O + 2NaOH → Na₂C₂O₄ + 4H₂O

Moles of NaOH can be calculated by using the below formulas:

M = n/V

n = 0.4500M / 0.020L = 0.0090 moles

From the stoichiometry of the reaction it is clear that:

2 moles of NaOH = react with 1 mole of H₂C₂O₄.2H₂O

0.0090 moles of NaOH = react with 1/2×0.0090=0.0045moles of H₂C₂O₄.2H₂O

Mass of H₂C₂O₄.2H₂O will be calculated by using the above formula of moles as:

Mass = 0.0045 mol × 126 g/mol = 0.567 grams

Hence, 0.567 grams is the required mass.

To know more about moles, visit the below link:

https://brainly.com/question/26092247