Respuesta :
The number of grams of oxalic acid dihydrate that are needed to react with 20.00 ml of 0.4500 M NaOH is 0.567 grams
calculation
Step 1: write the equation for reaction
H2C2 O4 . 2H2O + 2 NaOH → Na2C2O4 + 4 H2O
Step 2: calculate the moles of NaOH
moles = molarity x volume in liters
volume in liters = 20.00/1000 =0.0200 L
molarity =0.4500 M = 0.4500 mol/l
moles = 0.4500 mol/l x 0.0200 L =0.0090 moles
Step 3: use the mole ratio to calculate the of oxalic acid dihydrate
that is H2 C2O4: NaOH is 1:2 therefore the moles of H2C2O4.2H2O
=0.0090 moles x 1/2 =0.0045 moles
Step 4: calculate the mass of H2C2O4.2H2O
mass= moles x molar mass
the molar mass of H2C2O4.2H2O = (1x2)+ (12 x2) + (16 x4) + 2(18) =126 g/mol
mass =0.0045 moles x 126 g/mol =0.567 grams
0.567 grams of oxalic acid dihydrate, a diprotic acid are needed to react with 20.00 mL of 0.4500 M NaOH.
How we calculate mass of any substance from moles?
Mass of any substance will be calculated by using moles as:
n = W/M, where
W = required mass
M = molar mass
Given chemical reaction is :
H₂C₂O₄.2H₂O + 2NaOH → Na₂C₂O₄ + 4H₂O
Moles of NaOH can be calculated by using the below formulas:
M = n/V
n = 0.4500M / 0.020L = 0.0090 moles
From the stoichiometry of the reaction it is clear that:
2 moles of NaOH = react with 1 mole of H₂C₂O₄.2H₂O
0.0090 moles of NaOH = react with 1/2×0.0090=0.0045moles of H₂C₂O₄.2H₂O
Mass of H₂C₂O₄.2H₂O will be calculated by using the above formula of moles as:
Mass = 0.0045 mol × 126 g/mol = 0.567 grams
Hence, 0.567 grams is the required mass.
To know more about moles, visit the below link:
https://brainly.com/question/26092247