Answer:
a) 2KClO₃ → 2KCl + 3O₂
b) 2Al + 3I₂ → Al₂I₆
c) 2NaCl + H₂SO₄ → 2HCl + Na₂SO₄
d) H₃PO₄ + KOH → KH₂PO₄ + H₂O
Explanation:
a) KClO₃ → KCl + O₂
At first both K and Cl are balanced, so we balance O. In order to balance O we put a coefficient of 2 in KClO₃ and a coefficient of 3 in O₂:
2KClO₃ → KCl + 3O₂
Now we need to balance K and Cl, so we put a coefficient of two in KCl:
2KClO₃ → 2KCl + 3O₂
b) Al + I₂ → Al₂I₆
There are two Al atoms in the right side, so we write a coefficient of two in the left side. To balance I we write a coefficien of 3 in the left side:
2Al + 3I₂ → Al₂I₆
c) NaCl + H₂SO₄ → HCl + Na₂SO₄
We begin by balancing Na:
2NaCl + H₂SO₄ → HCl + Na₂SO₄
Then we balance Cl:
2NaCl + H₂SO₄ → 2HCl + Na₂SO₄
The equation is now balanced.
d) H₃PO₄ + KOH → KH₂PO₄ + H₂O
As is, the equation is already balanced.
