Find the slope of the line

let's notice, the line passes through (-2, 0) and (0, 3),
[tex]\bf (\stackrel{x_1}{-2}~,~\stackrel{y_1}{0})\qquad (\stackrel{x_2}{0}~,~\stackrel{y_2}{3}) \\\\\\ slope = m\implies \cfrac{\stackrel{rise}{ y_2- y_1}}{\stackrel{run}{ x_2- x_1}}\implies \cfrac{3-0}{0-(-2)}\implies \cfrac{3}{0+2}\implies \cfrac{3}{2}[/tex]
We can use the points (-2, 0) and (0, 3) to solve.
Slope formula: y2-y1/x2-x1
= 3-0/0-(-2)
= 3/2
Hope This Helped! Good Luck!