The perimeter of a rectangle is 88m if the width were doubled and the length were increased by 12m,the perimeter would be 152m what is the length of the original rectangle

Respuesta :

The answer is: The length of the original rectangle is 24 meters.

Explanation:

1. The perimeter of a rectangle is:

[tex]P=2L+2W[/tex]

Where [tex]L[/tex] is the length and [tex]W[/tex] is the width

2. The perimeter of the original rectangle is 88 meters, therefore:

[tex]88=2L+2W[/tex] (First equation)

3.  The width were doubled, the length were increased by 12 meters and the new perimeter is 152 meters. Therefore:

[tex]152=2(L+12)+2(2W)[/tex]

[tex]128=2L+4W[/tex] (Second equation)

4. As you can see, you have a system of equations:

[tex]\left \{ {{2L+2W=88} \atop2L+4W=128}} \right.[/tex]

5. You can solve it by applying the Elimination Method. Multiply the first equation by -1, add both equations and solve for [tex]W[/tex]:

[tex]\left \{ {{-2L-2W=-88} \atop2L+4W=128}} \right.[/tex]

[tex]2W=40\\W=20[/tex]

6. Now, you can calculate the lenght by substituying the width into one of the original equations:

[tex]2L+2(20)=88\\2L=48\\L=24[/tex]

The original length of the rectangle is [tex]\boxed{24{\text{ m}}}[/tex] and the width of the rectangle is [tex]\boxed{20{\text{ m}}}.[/tex]

Further explanation:

The perimeter the rectangles can be obtained as follows,

[tex]\boxed{{\text{Perimeter}} = 2l + 2w}[/tex]

Here, [tex]\text{l}[/tex] is the length and [tex]\text{w}[/tex] is the width.

Given:

The original perimeter of the rectangle is [tex]88{\text{ m}}.[/tex]

The increased perimeter of the rectangle is [tex]152{\text{ m}}.[/tex]

Explanation:

Consider the original length of the rectangle as [tex]\text{x}[/tex].

Consider the original width of the rectangle as [tex]\text{y}[/tex].

The original perimeter of the rectangle is [tex]88{\text{ m}}.[/tex]

[tex]\begin{aligned}2\left({x + y} \right) &= 88\\x + y &= \frac{{88}}{2}\\x + y &= 44\\x &= 44 - y\\\end{aligned}[/tex]

The length is increased by 12 and the width is double.

[tex]\begin{aligned}2\left( {x + 12 + 2y} \right) &= 152\\x + 12 + 2y &= \frac{{152}}{2}\\x + 2y &= 76 - 12\\x + 2y &= 64\\\end{aligned}[/tex]

Substitute [tex]44 - y[/tex] for [tex]\text{x}[/tex]

[tex]\begin{aligned}44 - y + 2y&= 64\\y&= 64 - 44\\y&= 20\\\end{aligned}[/tex]

The length can be obtained as follows,

[tex]\begin{aligned}x&= 44 - 20\\x&= 24\\\end{aligned}[/tex]

The original length of the rectangle is \boxed{24{\text{ m}}} and the width of the rectangle is [tex]\boxed{20{\text{ m}}}.[/tex]

Learn more:

  1. Learn more about inverse of the functionhttps://brainly.com/question/1632445.
  2. Learn more about equation of circle brainly.com/question/1506955.
  3. Learn more about range and domain of the function https://brainly.com/question/3412497

Answer details:

Grade: High School

Subject: Mathematics

Chapter: Rectangle

Keywords: 88 m, width, doubled, length, increases by 12, original rectangle, rectangles, perimeter, number of rectangles, 2 rectangles, 3 rectangles, table, between the sides, represents.