The perimeter of a △ABC equals 12 in. The midpoints of the sides M, N and K are connected consecutively. Find the perimeter of △MNK.

Respuesta :

Answer:

Perimeter of ΔMNK is 6 in.

Step-by-step explanation:

Midpoint Theorem-

It states that the segment joining two sides of a triangle at the midpoints of those sides is parallel to the third side and is half the length of the third side.

M, N and K are the midpoints of the sides.

So,

  1. [tex]KN=\frac{1}{2}AB[/tex]
  2. [tex]NM=\frac{1}{2}CA[/tex]
  3. [tex]MK=\frac{1}{2}BC[/tex]

Perimeter of a ΔABC is 12 in, i.e [tex]AB+CA+BC=12[/tex] in

Perimeter of ΔMNK is,

[tex]=KN+NM+MK[/tex]

[tex]=\dfrac{1}{2}AB+\dfrac{1}{2}CA+\dfrac{1}{2}BC[/tex]

[tex]=\dfrac{1}{2}(AB+CA+BC)[/tex]

[tex]=\dfrac{1}{2}(12)[/tex]

[tex]=6[/tex] in

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