See , from the equation we can see that for forming two mole of H2O 2Mole of H2 has to react.
Mass of 2 Mole H2O is 18*2gm or 36gm.
So for forming 36 gm H2O 2×2 I.e. 4 gm H2 has to take part in reaction.
Therefore, to form 1 gm H2O 4÷36 gm of H2 has to take part.
So, for forming 47gm H2O (4÷36)×47 gm H2 has to take part
I.e. 5.22 gm of H2 has to take part
So, ans is 5.22 gm of hydrogen.
Hope it helps!!!
Answer: Mass of hydrogen gas that must react will be 5.22 grams.
Explanation:
To calculate the number of moles, we use the equation:
[tex]\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}[/tex] ....(1)
Given mass of water = 47 g
Molar mass of water = 18 g/mol
Putting values in above equation, we get:
[tex]\text{Moles of }H_2O=\frac{47g}{18g/mol}=2.61mol[/tex]
For the given balanced chemical equation:
[tex]2H_2+O_2\rightarrow 2H_2O[/tex]
By Stoichiometry of the reaction:
2 moles of water are formed from 2 moles of hydrogen gas.
So, 2.61 moles of water will be formed from [tex]\frac{2}{2}\times 2.61=2.61mol[/tex] of hydrogen gas.
Now, calculating the mass of hydrogen by using equation 1:
Moles of hydrogen gas = 2.61 moles
Molar mass of hydrogen gas = 2 g/mol
Putting values in equation 1, we get:
[tex]2.61mol=\frac{\text{Mass of hydrogen gas}}{2g/mol}\\\\\text{Mass of hydrogen gas}=5.22g[/tex]
Hence, mass of hydrogen gas that must react will be 5.22 grams.
