Respuesta :
Answer:
a) [tex]\text{no of moles}=\frac{\text{given mass}}{\text{Molecular mass}}[/tex]
[tex]\text{no of moles of sucrose}=\frac{1.202g}{342g/mol}=0.0035moles[/tex]
b) Moles of carbon in 1 mole of sucrose [tex]C_{12}H_{22}O_{11}[/tex]= 12 moles
Moles of carbon in 0.0035 moles of sucrose [tex]C_{12}H_{22}O_{11}=\frac{12}{1}\times 0.0035=0.042moles[/tex]
Moles of hydrogen in 1 mole of sucrose [tex]C_{12}H_{22}O_{11}[/tex]= 22 moles
Moles of hydrogen in 0.0035 moles of sucrose [tex]C_{12}H_{22}O_{11}=\frac{22}{1}\times 0.0035=0.077moles[/tex]
Moles of oxygen in 1 mole of sucrose [tex]C_12H_22O_11[/tex]= 11 moles
Moles of oxygen in 0.0035 moles of sucrose [tex]C_{12}H_{22}O_{11}=\frac{11}{1}\times 0.0035=0.042moles[/tex]
c) 1 mole of carbon contains [tex]=6.023\times 10^{23}atoms[/tex]
0.042 moles of carbon contain [tex]=\frac{6.023\times 10^{23}}{1}\times 0.042=0.25\times 10^{23}atoms[/tex]
1 mole of hydrogen contains [tex]=6.023\times 10^{23}atoms[/tex]
0.077 moles of hydrogen contain [tex]=\frac{6.023\times 10^{23}}{1}\times 0.077=0.46\times 10^{23}atoms[/tex]
1 mole of oxygen contains [tex]=6.023\times 10^{23}atoms[/tex]
0.042 moles of oxygen contain [tex]=\frac{6.023\times 10^{23}}{1}\times 0.042=0.25\times 10^{23}atoms[/tex]
