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The time a basketball player spends in the air when shooting a basket is called the​ "hang time." the vertical leap l measured in feet is related to the hang time t measured in seconds by the equation equals=4t squared 4t2. suppose that a basketball player has a vertical leap of 44 feet 1111 inches. find the hang time for this leap.

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tramserran

Answer: 1.1 seconds

Step-by-step explanation:

leap = 4t²  ; leap = 4 ft 11 inches, find t

[tex]4\frac{11}{12} = 4t^2[/tex]

[tex]\frac{59}{12} = 4t^2[/tex]

[tex]\frac{59}{48} = t^2[/tex]

[tex]\sqrt{\frac{59}{12}} = \sqrt{t^2}[/tex]

[tex]\sqrt{1.23} = t[/tex]

1.1 = t


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