From the balanced equation 3 moles of oxygen are produced from 2 molecules of potassium chlorate.
So the number of moles of oxygen from 1 mole of chlorate = 3/2 = 1.5.
By proportion the number of moles produced from 6 moles of the chlorate =
= 6 * 1.5 = 9 moles (answer).
Considering the reaction stoichiometry, the correct answer is the last option: the total number of moles of O₂ produced by the decomposition of 6.0 moles of potassium chlorate is 9 moles.
The balanced reaction is:
2 KClO₃ → 2 KCl + 3 O₂
By reaction stoichiometry (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of moles of each compound participate in the reaction:
Then you can apply the following rule of three: if by stoichiometry 2 moles of KClO₃ produce 3 moles of O₂, 6 moles of KClO₃ will produce how many moles of O₂?
[tex]amount of moles of O_{2}=\frac{6 moles of KClO_{3} x 3moles of O_{2}}{2moles of KClO_{3} }[/tex]
amount of moles of O₂= 9 moles
Finally, the correct answer is the last option: the total number of moles of O₂ produced by the decomposition of 6.0 moles of potassium chlorate is 9 moles.
Learn more:
