A person drives an automobile with a mass of 450 kilograms at a velocity of 26 meters per second. The driver accelerates to a velocity of 30 meters per second. The difference in the automobile’s kinetic energy between the two velocities is joules. You may use the calculator.

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georgestirban georgestirban · Answer 1 · 2018-12-22T14:49:45+01:00

Ec₁=mv₁²/2=450*26²/2=225*676=152100 J

Ec₂=mv₂²/2=450*30²/2=225*900=202500 J

ΔEc=Ec₂-Ec₁=202500-152100=50.4 kJ

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Eduard22sly Eduard22sly · Answer 2 · 2021-08-12T20:36:02+02:00

To answer the question, we shall determine the kinetic energy of the automobile in each case. This can be obtained as illustrated below:

Mass (m) = 450 Kg

Velocity (v₁) = 26 m/s

KE₁ = ½mv₁²

KE₁ = ½ × 450 × 26²

KE₁ = 225 × 676

Mass (m) = 450 Kg

Velocity (v₂) = 30 m/s

KE₂ = ½mv₂²

KE₂ = ½ × 450 × 30²

KE₂ = 225 × 900

Finally, we shall determine the difference in the kinetic energy of the automobile. This can be obtained as illustrated below:

Kinetic energy of case 1 (KE₁) = 152100 J

Kinetic energy of case 2 (KE₂) = 202500 J

Difference = KE₂ – KE₁

Difference = 202500 – 152100

Therefore, the difference in the kinetic energy of the automobile is 50400 J

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