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Answer:
The coordinate of pre-image is, B(3 , -9).
Step-by-step explanation:
Given an image point has coordinate B'(7, -4).
We have to find the coordinates of its pre-image:
The rule of translation on pre-image (x, y) is given by;
[tex]B(x, y) \rightarrow B'(x + 4, y + 5)[/tex]
then;
(7, -4) = (x+4, y+5)
on comparison we have;
x+4 = 7 and y + 5 = -4
First solve for x;
[tex]x + 4 = 7[/tex]
Subtract 4 from both sides we have;
x + 4 -4 =7-4
Simplify:
x = 3
To solve for y;
y+5 = -4
Subtract 5 from both sides we get;
y = -9
Therefore, the coordinate of pre-image is, B(3, -9)
Answer:
The coordinate of pre-image is, B(3 , -9).
Step-by-step explanation:
Given an image point has coordinate B'(7, -4).
We have to find the coordinates of its pre-image:
The rule of translation on pre-image (x, y) is given by;
then;
(7, -4) = (x+4, y+5)
on comparison we have;
x+4 = 7 and y + 5 = -4
First solve for x;
Subtract 4 from both sides we have;
x + 4 -4 =7-4
Simplify:
x = 3
To solve for y;
y+5 = -4
Subtract 5 from both sides we get;
y = -9
Therefore, the coordinate of pre-image is, B(3, -9)
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