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An engineer on the ground is looking at the top of a building. The angle of elevation to the top of a buliding. The angle of elevation to the top of the building is 22°. The engineer knows the building is 450 ft tall. What is the distance from the engineer to the base of the building to the nearest whole foot?

Respuesta :

SFM19613

[tex] \tan( \alpha ) \: = \: \frac{h}{b} [/tex]
[tex] \alpha \: = \: {22}^{0} [/tex]
[tex]h \: = \: 450 \: ft[/tex]
Therefore,
[tex]b \: = \: h \cot( \alpha ) [/tex]
[tex]b \: = \: 450 \: ft \: \times \: \cot( {22}^{0} ) [/tex]
b = 450 ft × 2.47508685
b = 1,113.78908 ft
or,
b ≈ 1,114 ft.
5431857

Answer:

1,114 ft

Step-by-step explanation:

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