A gardener is planting two types of trees: Type A is 8 feet tall and grows at a rate of 3 inches per year. Type B is 7 feet tall and grows at a rate of 4 inches per year. Algebraically determine exactly how many years it will take for these trees to be the same height.

Respuesta :

Answer:

Exactly 12 years it will take for these trees to be the same height

Step-by-step explanation:

Slope intercept form: An equation of line is in the form of [tex]y = mx+b[/tex] where m is the slope or unit rate and b is the y-intercepts.

Let x represents the time in years and y represents the height of the tree.

Use conversion:

1 ft = 12 inches

As per the given statement:

Type A is 8 feet tall and grows at a rate of 3 inches per year.

⇒unit rate per year = 3 inches = [tex]\frac{1}{4}[/tex] ft

Then, we have;

[tex]y =\frac{1}{4}x + 8[/tex]                      ......[1]

Similarly for;

Type B  is 7 feet tall and grows at a rate of 4 inches per year.

⇒unit rate per year = 4 inches = [tex]\frac{1}{3}[/tex] ft

then;

[tex]y =\frac{1}{3}x + 7[/tex]                   .....[2]

To find after how many years it will take for these trees to be the same height.

Since, trees to be the same height;

⇒equate [1] and [2], to solve for x;

[tex]\frac{1}{4}x + 8 = \frac{1}{3}x +7[/tex]

Subtract 7 from both sides we get;

[tex]\frac{1}{4}x + 8-7= \frac{1}{3}x +7-7[/tex]

Simplify:

[tex]\frac{1}{4}x + 1= \frac{1}{3}x[/tex]

Subtract [tex]\frac{1}{4}x[/tex] from both sides we get;

[tex]1= \frac{1}{3}x-\frac{1}{4}x[/tex]

Simplify:

[tex]1 = \frac{x}{12}[/tex]

Multiply both sides by 12 we get;

x = 12

Therefore, exactly it will take for these trees to be the same height is, 12 years