Respuesta :
Answer: The empirical formula of the compound is [tex]Ca(OH)_2[/tex]
Explanation:
To find the empirical formula of the compound, we follow following steps:
- Step 1: Finding the number of moles of the given elements.
To calculate the number of moles, we use the formula:
[tex]\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}[/tex]
- For Calcium:
Molar mass of calcium = 40 g/mol
Given mass of calcium = 13.5 g
Putting values in above equation, we get:
[tex]\text{Number of moles}=\frac{13.5g}{40g/mol}=0.3375[/tex]
- For Oxygen:
Molar mass of oxygen = 16 g/mol
Given mass of oxygen = 10.8 g
Putting values in above equation, we get:
[tex]\text{Number of moles}=\frac{10.8g}{16g/mol}=0.675[/tex]
- For Hydrogen:
Molar mass of hydrogen = 1 g/mol
Given mass of hydrogen= 0.675 g
Putting values in above equation, we get:
[tex]\text{Number of moles}=\frac{0.675g}{1g/mol}=0.675[/tex]
- Step 2: Now, to obtain the mole ratio, we divide the moles of each element by the smallest number of moles calculated.
For Ca = [tex]\frac{0.3375}{0.3375}=1[/tex]
For H = [tex]\frac{0.675}{0.3375}=2[/tex]
For O = [tex]\frac{0.675}{0.3375}=2[/tex]
The ratio of Ca : O : H = 1 : 2 : 2
- Step 3: Now, the ratio of the elements is represented as the subscripts in the empirical formula.
The formula becomes: [tex]CaO_2H_2\approx Ca(OH)_2[/tex]
Hence, the empirical formula of the compound is [tex]Ca(OH)_2[/tex]
