Answer:
Confidence interval estimate of the mean weight of plastic discarded by all households is : (1.561 , 2.261)
Step-by-step explanation:
Sample size, n = 62
[tex]\text{Mean, }\bar{x}=1.911\\\text{Standard Deviation, }\sigma = 1.065\\\text{Now, for 99 percent level of confidence, z* = 2.58}\\\\\text{Margin of Error = }z^*\times \frac{\sigma}{\sqrt{n}}\\\\=2.58\times \frac{1.065}{\sqrt{62}}\\\\=2.58\times \frac{1.065}{7.87}\\\\\implies \text{Margin of Error = }0.35 [/tex]
Now the Confidence interval is : Mean ± Margin of Error
= (1.911 - 0.35 , 1.911 + 0.35)
= (1.561 , 2.261)
Hence, Confidence interval estimate of the mean weight of plastic discarded by all households is : (1.561 , 2.261)
