which congruence theorem can be used to prove ABC is congruent to DEF?

Answer: AAS
Step-by-step explanation:
Given: In ΔABC and ΔDEF
∠B≅∠E [right angle]
∠A≅∠D
[tex]\overline{BC}\cong\overline{EF}[/tex]
As there is two angles and one non included side of ΔABC is congruent the two corresponding angles and one non- included side of ΔDEF, therefore, by AAS congruence rule.
ΔABC ≅ΔDEF
AAS congruence postulate :- Triangles are congruent if two pairs of corresponding angles and a pair of opposite sides are equal in both triangles.