contestada

During tug-of-war, team A does 2.20*10^5 J of work in pulling team B 8.00m. What average force did team A exert

Respuesta :

As we know that work done is defined as product of force and displacement

so here we will have

[tex]W = F.d[/tex]

so here we know that

[tex]W = 2.20 \times 10^5 J[/tex]

also we know that

[tex]d = 8.00 m[/tex]

now we will have

[tex]2.20 \times 10^5 = F(8.00)[/tex]

[tex]F = \frac{2.20 \times 10^5}{8}[/tex]

[tex]F = 27500 N[/tex]

so it will have 27500 N force on it

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