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The sum of three consecutive even integers is 72. Let x represent the first integer, x + 2 represent the second integer, and x + 4 represent the third integer.

Which equation can be used to find the first integer?

Respuesta :

Hello from MrBillDoesMath!

Answer:

The equation is  x + ( x+ 2) + (x+4 ) = 72    

(while not asked, x = 22 is the solution)



Discussion:

We are given that

x + ( x+ 2) + (x+4 ) = 72 =>             (combine like terms)

3x + 6 = 72                   =>             (subtract 6 from each side)

3x = 72 -6 = 66            =>

x = 66/3  = 22              



Thank you,

MrB

isyllus

Answer:

Equation used:

x + x + 2 + x + 4 = 72

x = 22

Step-by-step explanation:

The sum of three consecutive even integers is 72.

First integer = x

Second integer = x+2

Third integer = x + 4

According to question, sum of all three even integers is 72

Therefore,

x + x + 2 + x + 4 = 72   (This equation is used to find x)          

               3x + 6 = 72

                     3x = 66

                       x = 22

Hence, The first equation is 22.

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