Answer: 39.2 m/s
Explanation:
Initial velocity of the ball, u = 19.6 m/s
final velocity of ball, v
Time, t = 2.0 s
The ball would accelerate due to gravity,
a = g = 9.8 m/s²
Using first equation of motion:
v = u + a t
⇒ v = 19.6 m/s + 9.8 m/s² × 2.0 s = 39.2 m/s
Thus, the velocity of ball after 2.0 s of release would be 39.2 m/s
