Coulomb's law:
F = k×q₁×q₂/r² where k ≈ 9.00×10⁹NC⁻²m²
Given values:
q₁ = +1.0C
q₂ = -1.0C
F = 650N
Substitute the terms in Coulomb's law with our given values. We will have to use the absolute value of q₂ to so the algebra works out. Solve for r:
650 = 9.00×10⁹×1.0×1.0/r²
r = 3721m
Taking significant figures into account:
Answer:
The answer is 3721.04 m
Explanation:
To solve the exercise, we will use the expression of force of attraction or repulsion between two electric charges:
F = (k*q1*q2)/d^2, where
F = force of attraction = 650 N
q1 and q2 are the charge
k = electric proportionality constant = 9 x 10^9 N x m^2
Clearing d, we have:
d = ((k*q1*q2)/F)^1/2 = ((9x10^9*1*1)/(650))^1/2 = 3721.04 m
