ANSWER
E. 10 and 640
EXPLANATION
The given series is
[tex]\sum_{i=1}^45 \times 2^{2i-1}[/tex]
To find the first term of the series we substitute i=1 to get,
[tex]a_1 = 5 \times {2}^{2 \times 1 - 1} [/tex]
[tex]a_1 = 5 \times {2}^{ 1} = 10[/tex]
For the last term of the series, we substitute i=4 to obtain,
[tex]a_4 = 5 \times {2}^{2 \times 4 - 1} [/tex]
[tex]a_4 = 5 \times {2}^{7} [/tex]
This implies that,
[tex]a_4 = 5 \times 128 = 640[/tex]
Therefore the correct answer is E
