Answer:
473 in²
Step-by-step explanation:
We have four congruent triangles and a square in the base.
The formula of an area of a triangle:
[tex]A_\triangle=\dfrac{1}{2}bh[/tex]
b - base
h - height
The formyla of an area of a square:
[tex]A_{\boxed{}}=a^2[/tex]
a - length of side
We have b = 11 in, h = 16 in and a = 11 in. Substitute:
[tex]A_\triangle=\dfrac{1}{2}(11)(16)=(11)(8)=88\ in^2\\\\A_{\boxed{}}=11^2=121\ in^2[/tex]
The Surface Area :
[tex]S.A.=4A_\triangle+A_{\boxed{}}[/tex]
Substitute:
[tex]S.A.=4(88)+121=352+121=473\ in^2[/tex]
