Respuesta :
Answer: The answer is (b) Neither I nor II.
Step-by-step explanation: We are given two equations and we need to find which is true. Since it is a simple algebraic question, so we just need to follow BODMAS rule to check the equations.
The equations are as follows -
[tex](I)~~L.H.S=(\dfrac{32}{8}-2)6=(4-2)6=2\times 6=12.[/tex]
[tex]R.H.S=(32-1)2=31\times 2=62.[/tex]
Since L.H.S ≠ R.H.S, so this equation is not correct.
[tex](II)~~L.H.S=\dfrac{72}{9\times 4}=2.[/tex]
[tex]R.H.S=\dfrac{62}{6+3}=\dfrac{62}{9}.[/tex]
Since L.H.S ≠ R.H.S, so this equation is also not correct.
Thus, the correct option is (b) Neither I nor II.
Answer:
Neither I nor II
Step-by-step explanation:
We will simplify both the sides of the given equations,
Equation I. [tex](\frac{32}{8}-2)^{6}=(32-1)^{2}[/tex]
i.e. [tex](4}-2)^{6}=(31)^{2}[/tex]
i.e. [tex]2^{6}=(31)^{2}[/tex]
i.e. 64=961, which is not true.
Equation II. [tex]\frac{72}{9\times 4}=\frac{62}{6+3}[/tex]
i.e. [tex]\frac{72}{36}=\frac{62}{9}[/tex]
i.e. 2 = 6.9, which is not true.
Hence, neither of the equations are true.
